A sample of oak has a density of 807 kilograms per cubic meter. The sample is in the shape of a cube, where each edge has a length of 0.90 meters. To the nearest whole number, what is the mass, in kilograms, of this sample?

Solution:

Given, 

density = $\rho = 807 Kg/ m^3$

Side of Cube = a = 0.9 m 

Volume = V =  $a^3 = (0.9m)^3$

Formula , $\rho = \frac{m}{V}$

$807 Kg/ m^3 = \frac{m}{(0.9m)^3}$

m = $807*(0.9)^3 Kg$

m = 588.3 Kg