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Question:
$\sqrt[6]{\frac{1}{2}}\sqrt[6]{128}$
Solution:
Remember, $\sqrt[a]{c}\sqrt[a]{d} = \sqrt[a]{cd}$
So, $\sqrt[6]{\frac{1}{2}}.\sqrt[5]{128}$
$=\sqrt[6]{\frac{1}{2}.{128}}$
$= \sqrt[6]{64}$
We know, 64 = 2.2.2.2.2.2 = $2^{6}$
$= \sqrt[6]{2^{6}}$
$= 2^{\frac{6}{6}}$
$= 2^{1}$
$= 2$
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