Janet wants to find the spring constant of a given spring, so she hangs the spring vertically and attaches a 0.49 kg mass to the spring's other end. If the spring stretches 3.6 cm from its equilibrium position, what is the spring constant?

Janet wants to find the spring constant of a given spring, so she hangs the spring vertically and attaches a 0.49 kg mass to the spring's other end. If the spring stretches 3.6 cm from its equilibrium position, what is the spring constant?

on January 30, 2023

Given :

m=0.49 Kg

x=3.6 cm = 0.036 m

F= m*g = (0.49Kg)(9.8m/s^2) = 4.802 Kgm/s^2 = 4.802 N

The Spring Constant is : $k=\frac{F}{x}$

So, $k =\frac{4.802 N}{0.036 m}$

k = 133.38889 N/m

k = 133.4 N/m

Comments