Solve the Quadratic Equation: 2x^2 - 3x +1 = 0

Question:

$2x^2 - 3x +1 = 0$

Solution:

$2x^2 - 3x +1 = 0$

$2x^2 - 2x - x +1 =0$

2x(x-1)-1(x-1) =0

(2x-1)(x-1) = 0

Now, 

x -1 = 0 and 2x -1 = 0 

x = 1 and x = $\frac{1}{2}$

x = 1, $\frac{1}{2}$